(12x^2-5x+4)/(3x+1)

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Solution for (12x^2-5x+4)/(3x+1) equation: 


D( x )

3*x+1 = 0

3*x+1 = 0

3*x+1 = 0

3*x+1 = 0 // - 1

3*x = -1 // : 3

x = -1/3

x in (-oo:-1/3) U (-1/3:+oo)

(12*x^2-(5*x)+4)/(3*x+1) = 0

(12*x^2-5*x+4)/(3*x+1) = 0

12*x^2-5*x+4 = 0

12*x^2-5*x+4 = 0

DELTA = (-5)^2-(4*4*12)

DELTA = -167

DELTA < 0

1 = 0

1/(3*x+1) = 0

x belongs to the empty set

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